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12a^2-6=7a
We move all terms to the left:
12a^2-6-(7a)=0
a = 12; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·12·(-6)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{337}}{2*12}=\frac{7-\sqrt{337}}{24} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{337}}{2*12}=\frac{7+\sqrt{337}}{24} $
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